543. Diameter of Binary Tree
Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of thelongestpath between any two nodes in a tree. This path may or may not pass through the root.
Example:
Given a binary tree
1
/ \
2 3
/ \
4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Thoughts:
- Need two paths, a open path from the left and right and a closed path from the left and right
Code
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def diameterOfBinaryTree(self, root):
"""
:type root: TreeNode
:rtype: int
"""
def helper(root):
if not root:
return (0 , 0)
left = helper(root.left)
right = helper(root.right)
return (max(left[0], right[0]) + 1 , max(left[0] + right[0] + 1, max(left[1], right[1]))) # (node numbers of open path , node numbers of of closed path)
if not root:
return 0
return helper(root)[1] - 1 # for node number > 0, path = node -1