## 122. Best Time to Buy and Sell Stock II

Say you have an array for which thei_thelement is the price of a given stock on day_i.

Design an algorithm to find the maximum profit. You may complete as many transactions as you like (i.e., buy one and sell one share of the stock multiple times).

Note:You may not engage in multiple transactions at the same time (i.e., you must sell the stock before you buy again).

Example 1:

``````Input: [7,1,5,3,6,4]

Output: 7

Explanation: Buy on day 2 (price = 1) and sell on day 3 (price = 5), profit = 5-1 = 4.
Then buy on day 4 (price = 3) and sell on day 5 (price = 6), profit = 6-3 = 3.
``````

Example 2:

``````Input: [1,2,3,4,5]

Output: 4

Explanation: Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit = 5-1 = 4.
Note that you cannot buy on day 1, buy on day 2 and sell them later, as you are
engaging multiple transactions at the same time. You must sell before buying again.
``````

Example 3:

``````Input: [7,6,4,3,1]

Output: 0

Explanation:  In this case, no transaction is done, i.e. max profit = 0.
``````

Thoughts:

1. Greedy buy today's stock if tomorrow it will increase its price

Code

``````class Solution(object):
def maxProfit(self, prices):
"""
:type prices: List[int]
:rtype: int
"""
profit = 0
for i, p in enumerate(prices[:-1]):
if prices[i + 1] > p:
profit += prices[i + 1] - p
return profit
``````

Code: One line

``````class Solution(object):
def maxProfit(self, prices):
"""
:type prices: List[int]
:rtype: int
"""
return sum([b - a if b > a else 0 for a, b in zip(prices, prices[1:])])
``````